-2sin^2(x)+cos(x)+1=0

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Solution for -2sin^2(x)+cos(x)+1=0 equation: 


Simplifying
-2sin2(x) + cos(x) + 1 = 0

Multiply in2s * x
-2in2sx + cos(x) + 1 = 0

Multiply cos * x
-2in2sx + cosx + 1 = 0

Reorder the terms:
1 + cosx + -2in2sx = 0

Solving
1 + cosx + -2in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + cosx + -1 + -2in2sx = 0 + -1

Reorder the terms:
1 + -1 + cosx + -2in2sx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + cosx + -2in2sx = 0 + -1
cosx + -2in2sx = 0 + -1

Combine like terms: 0 + -1 = -1
cosx + -2in2sx = -1

Add '2in2sx' to each side of the equation.
cosx + -2in2sx + 2in2sx = -1 + 2in2sx

Combine like terms: -2in2sx + 2in2sx = 0
cosx + 0 = -1 + 2in2sx
cosx = -1 + 2in2sx

Divide each side by 'osx'.
c = -1o-1s-1x-1 + 2in2o-1

Simplifying
c = -1o-1s-1x-1 + 2in2o-1

Reorder the terms:
c = 2in2o-1 + -1o-1s-1x-1

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